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what is the cause of this condition?

2006-12-15 14:59:37 · 6 answers · asked by Erin D 2 in Science & Mathematics Medicine

6 answers

Supposing you really know that the number of glucose carriers is normal, your blood must be overloaded with glucose. This overwhelms the carriers in the nephrons, resulting in elevated urine glucose.

This is seen in diabetes, whether insulin-dependent or non-.

2006-12-15 15:07:12 · answer #1 · answered by RolloverResistance 5 · 2 0

A level of glucose processed through the kidneys that is greater than around 350 mg/min(in the average kidney). That is about the max amount of glucose that can be processed by the kidneys, any more and it can't be reabsorbed and gets expelled in the urine. Glycosuria is typically caused by diabetes, but really anything that affects the nephron can cause it.

2006-12-15 15:07:34 · answer #2 · answered by Tadgie1 3 · 1 0

If the blood glucose concentration goes over the renal threshold of glucose reabsorption, then not enough glucose transporters are capable of reabsorbing the high blood glucose concentration, hence glucose is excreted in the urine.

2006-12-15 15:44:40 · answer #3 · answered by potbox 2 · 0 0

If there is no renal tubular defects involving amino acid excretion in urine and acidosis, it maybe due t6 a condition called renal glycosuria, or renal diabetes.

If everything else is normal upon testing for tubular functions etc, then it might be due to an inherited trait.(usually autosomal dominant).

This diagnosis will be conclusive after a few tests to be ordered by your doctor.

2006-12-15 15:17:36 · answer #4 · answered by QuiteNewHere 7 · 0 0

The first thing that will be checked will be blood sugar levels. If blood sugar levels are normal then the kidneys would be investigated but the usual and most common cause if diabetes melllitus.

2006-12-15 18:07:10 · answer #5 · answered by mr.answerman 6 · 0 0

This would be either type I or Type II diabetes.

2006-12-15 15:27:26 · answer #6 · answered by TomB 3 · 0 0

diabetes

2006-12-15 15:01:55 · answer #7 · answered by joshua 1 · 1 0

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