Please answer/confirm/correct:
?A ti te gusta correr?= Is running pleasing to you?( do you like running?)
A mi me gusta correr= Running is pleasing to me( I like running)
!No digas eso!= ????
?Quien es? = WHo is it?
?De quien es la mochila...= Whose back pack is this?
Es de mi= It is mine
Thank you !
2006-12-14 12:29:07 · 8 answers · asked by luna y 1 in Society & Culture ➔ Languages
¿A ti te gusta correr? - Do you like to run?
A mi me gusta correr - I like to run
¡No digas eso! - Don´t say that!
Es mío - It´s mine
Gracias - Thank you!
2006-12-14 13:30:46 · answer #1 · answered by Trigueña 6 · 0⤊ 1⤋
No digas eso = don´t say that
Es de mi should be changed to say "Es mía"
quién should have an accent
Great job!
2006-12-14 12:36:56 · answer #2 · answered by Martha P 7 · 1⤊ 2⤋
!No digas eso!= Do not say that!
Es de mi= It is mine (sounds better "Es Mia")
Other than that you are ok
2006-12-14 12:31:54 · answer #3 · answered by Cisco Sucks 3 · 1⤊ 2⤋
No digas eso- dont say that
2006-12-14 13:45:51 · answer #4 · answered by xoxchelaxox08 2 · 1⤊ 1⤋
They are OK.
"No digas eso" means "don't say that"
"Es de mi" is not used. Better "es mio"
2006-12-14 12:33:15 · answer #5 · answered by PragmaticAlien 5 · 0⤊ 3⤋
1) Is running pleasing to you? (Do you like running?)
-- ¿Corre complaciendo a usted?
2) Running is pleasing to me. (I like running.)
-- Correr complace a mí.
3) Not to say that! (Don't say that!)
-- !No digas eso!
4) Whose back pack is this?
-- ¿Cuyo apoya paquete es esto?
5) It is mine.
-- Es mío.
~*~♥ Gracias ♥~*~
2006-12-14 12:36:22 · answer #6 · answered by ♥April♥ 2 · 0⤊ 4⤋
do you like running? = ¿tú tienen gusto de funcionar?
I like running = Tengo gusto de funcionar
You do not say that! = !No digas eso!
Don't say that = ¡no decir eso!
Whose back pack is this= ¿De quién morral es éste?
It is mine= Es el mío
2006-12-14 12:41:14 · answer #7 · answered by R2 3 · 0⤊ 4⤋
Go to http://babelfish.yahoo.com. You can check the answers there.
http://www.handlethetruth.net
2006-12-14 12:36:47 · answer #8 · answered by truthhandlr 2 · 1⤊ 2⤋