As with typical TV quiz things there are several possible answers because the question isn't specific.
It could be 55 - if all the dogs meet one another and are brothers.
It could be 220 - if 55 dogs met 55 others you would have 110, give them all brothers and you have 220.
It could be 110 (even though you've already said no to this answer) - if the 55 dog's new buddies are actually their brother's then this would be the answer.
I think there are other possibilities too, but can't be bothered to sit here and write them all out.
2006-12-13 09:09:17
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answer #1
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answered by mad_caesar 3
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55 dogs met 1 dog each: 55 + 55 = 110
have game with 55 other dogs: 110+55= 165
to answer the same as everyone else and get best answer: priceless
ha ha 165
2006-12-13 13:23:11
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answer #2
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answered by Sheldon 6
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If 55 dogs each meet 1 dog that gives you 110 then they met their 55 brothers and that gives you 165
2006-12-13 14:19:49
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answer #3
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answered by sharlene j 2
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165 dogs
55 dogs + 55 dogs they meet + 55 doggie brothers.
2006-12-13 12:37:48
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answer #4
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answered by JB 2
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55 dogs meet 1 dog each so now you have 110 dogs.
they each have a game with their doggie brothers (assuming 1 brother each) then you have 220 dogs!!
also assuming that none of the dogs are already brothers or that when they meet 1 dog each it is a new dog and not one of the original 55!!!
2006-12-13 12:35:33
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answer #5
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answered by Anonymous
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55 you never said they meet a new dog
2006-12-13 12:59:12
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answer #6
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answered by kez_124 4
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2 doggie dogs playing a frisbee game..whatever it is...the other dog..probably wearing a number 55...don't know..just a guess
2006-12-13 12:38:17
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answer #7
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answered by Anonymous
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What the hell is 56 or whatever dogs doing at the park together? And what park is it? I want to avoid it and dogs can't play frisbee
2006-12-13 15:01:17
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answer #8
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answered by Virg 2
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there are 55 dogs...they meet eache other..and play frisbee with each other...they all are brothers
2006-12-13 12:37:23
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answer #9
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answered by adi 2
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There are 56 dogs in the park playing frisbee! it's an easy answer if u actually think about what and how the question is being asked
2006-12-13 12:36:11
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answer #10
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answered by Tara M 2
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