2006-12-13 02:30:45 · 28 answers · asked by Anonymous in Pets ➔ Dogs
111
2006-12-13 02:42:49 · answer #1 · answered by Michael D 6 · 2⤊ 1⤋
2
2006-12-13 10:34:51 · answer #2 · answered by Anonymous · 0⤊ 1⤋
55=1 dog each=110 + 55 doggy brothers = 165 is the answer.
2006-12-13 10:38:01 · answer #3 · answered by Anonymous · 0⤊ 1⤋
a) 55 + 55 + 55 = 165 or
b) 55 + 55 = 110 + (110 x 55) =6050 = 6160 and 1 frisbee lol
55 dogs + 55 other dogs if all 110 dogs had a combined total of 55 brothers that would equal 6050 add the original 110 = 6160.
So who's throwing the frisbee ??
2006-12-13 10:41:22 · answer #4 · answered by Just Me 6 · 0⤊ 1⤋
there would be 165 dogs 55 +1 each is 110 + 55 of the brothers = 165
2006-12-13 10:35:23 · answer #5 · answered by adriennebabcock19 1 · 1⤊ 1⤋
It's 110...
55 dogs meet 1 dog each = 55 dogs meet other 55 dogs =110.
They play with their doggy brothers = Every dog but the 55 met later is all dog's brother, so each dog is playing with it's brother = 110.
Is it right?
PS.- How many frisbees? :-D
2006-12-13 10:46:27 · answer #6 · answered by Stefano - [Freddie Mercury] 1 · 0⤊ 1⤋
55
2006-12-13 10:34:45 · answer #7 · answered by beanie 5 · 0⤊ 1⤋
55 + 1 each=110.
If the dogs they have met are their Brothers, then there would be 110.
If the Dogs they met, weren't their Brothers, then add another 55 which =165. Am i right??? But this is as long as you are meaning 'Dogs' as Males, not a mixture of Bitches and Dogs. MMMMmmmmm. Confusing!!!!
2006-12-13 10:45:32 · answer #8 · answered by S 4 · 0⤊ 2⤋
55 plus 1x55 equals 110 dogs.
2006-12-13 11:31:00 · answer #9 · answered by PetLover 4 · 0⤊ 1⤋
165
2006-12-13 11:07:17 · answer #10 · answered by Billy K 2 · 0⤊ 1⤋