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This field should be according to Gauss's Law

2006-12-13 02:11:26 · 4 answers · asked by Don 1 in Science & Mathematics Engineering

4 answers

wel the electric filed can not exist without a charge. this thing is clear. now for a +ive charge the electric filed is outwards and for the -ive charge electric filed is inwards. as far as the conductor is concerned u have to look for the geometry of the conductor. for a line conductor u will consider the distance in the guass's law by dividing the line conductors in small parts. similarly in the case of uniform bodies u will look for the symetry since guass's law deals with symmetirc charged bodies.

2006-12-13 02:53:20 · answer #1 · answered by Nabeel 2 · 0 0

It follows Gauss's law and the geometry of the field depends on the shape of the conductor.

2006-12-13 02:14:16 · answer #2 · answered by Gene 7 · 0 0

submit #4 gave a proof for static fields. For dynamic fields, the propagating (vacationing) wave is small in a conductor and the common wave result's an evanescent (decaying) wave. Evanescent waves decay exponentially. So, in different words, there somewhat is a small electric powered field interior a conductor, although that's sufficiently small to be negligible observing the conductivity and frequency of interest. that's sometimes defined by ability of the exterior intensity - as quickly as you get previous the exterior intensity of a conductor, the sector amplitude has fallen to a million/e (sure, the exponential) of that's loose area fee, approximately 37%.

2016-12-11 08:18:54 · answer #3 · answered by hume 4 · 0 0

the field points outward from the conductor if it is +vely charged otherwise it is inward

2006-12-13 02:23:23 · answer #4 · answered by sheesnhan 2 · 0 0

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