2006-12-11 13:34:38 · 6 answers · asked by charles b 1 in Science & Mathematics ➔ Engineering
RMS multiplied by 2.828 (2 times the square root of two) equals peak to peak.
Because:
RMS x sqrt (2) = peak
Peak * 2 = peak to peak
2006-12-11 13:42:36 · answer #1 · answered by Ron E 5 · 0⤊ 0⤋
For a sinewave, the peak to RMS ratio is sqr(2), say 1.41
Since the peak to peak is twice the peak value, the ratio of the peak to peak to RMS is 2.82, eg 2.82Vpp=1Vrms
2006-12-11 14:15:01 · answer #2 · answered by Eng_helper 2 · 1⤊ 0⤋
You can't -- unless you make some assumptions, such as your signal is a sine wave (in which case the other respondents gave the correct answer).
2006-12-11 14:57:32 · answer #3 · answered by Imager 2 · 1⤊ 0⤋
RMS=0.707*PP
Hence, PP=RMS/0.707
2006-12-11 13:46:41 · answer #4 · answered by LeAnne 7 · 0⤊ 1⤋
RMS Voltage = SQRT(V^2)
and for sinusoidal voltage;
Vrms = SQRT({V^2cos^2(wt0)}) = V*SQRT(cos^2(wt))
so,
Vrms = V / SQRT(2)
2006-12-11 13:49:31 · answer #5 · answered by Anonymous · 0⤊ 1⤋
it depends what type of wave you have: sine wave, square wave, etc.
You probably have a sine wave so RMS = (1/sqrt(2))*PP
2006-12-11 15:37:05 · answer #6 · answered by sharke45 2 · 0⤊ 1⤋