2006-12-11 01:29:53 · 4 answers · asked by Ian D 1 in Science & Mathematics ➔ Engineering
Xl = 2*pi*f*L = 2*3.14*10000*.015
2006-12-11 01:40:03 · answer #1 · answered by Ron E 5 · 0⤊ 0⤋
XL = Omega x L = 2 x Pi x f x L = 2 x Pi x 10 000 x 0.015 = 300 x Pi = 942 [Ohms], approximately. (Pi is slightly greater than 3.14 so the exact value would be a bit more, but the result is exact enough for engineering purposes, being well within 1%.)
2006-12-11 02:17:03 · answer #2 · answered by kalacihu 2 · 1⤊ 0⤋
X= j * 2 * pi * .015 H * 10000 Hz
Do the arithmetic
2006-12-11 01:46:52 · answer #3 · answered by Gene 7 · 0⤊ 0⤋
X=2πνL
ν = frequency in hertz
X is the inductive reactance, measured in ohms
ν is the frequency, measured in hertz
L is the inductance, measured in henries
L = 15 mh = 1.5x10^(-6) h
ν = 10kHz = 10000 Hz
X= 2π[1.5x10^(-6)h](10000 Hz) = 0.0942 h/s
X = 0.0942 h/s = 0.094 Ω
2006-12-11 01:48:41 · answer #4 · answered by rm 3 · 0⤊ 2⤋