Enough solar panels to generate around 2,235 J/s plus whatever else is lost in any conversion process you might require to convert the DC output of the solar panels to match the motors requirements (which will be, typically, 110V, 60 Hz, and a bit over 20 amps)
2006-12-13 21:53:41
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
I'm afraid that you might not like the answer.
First, it depends on the voltage of your system. You're running 12 volts on your solar system? In that case, since power (watts) are volts X amps, you're going to have to have a very large solar array--or some pretty good-sized batteries--to start your compressor. Air compressor motors are notorious for high starting currents, and DC compreesor motors are no exception. Not long ago (a couple of years) I helped a fellow install his solar-powered system in a cabin 'way up in the Cascades, and his system included a 1 horsepower, 12 volt air compressor. That compressor took 80 Amps to start and to run at close to the air pressures that he wanted to achieve.
While the amperage increase of these motors is not linear with the power increase--a 1/4 horse air compressor motor typically needs 25 amps, and 1 horsepower isn't three times 1/4 (though the power requirement is three times the smaller motor), your 3-horsepower air compressor can be expected to take at least twice that power, over 150 amps to start at 12 volts.
Perhaps you should think about a gasoline-run or propane-powered air compressor of that size? Maybe go with a 24 volt or even 48 volt system for the compressor?
2006-12-10 04:28:01
·
answer #2
·
answered by eutychusagain 4
·
0⤊
0⤋
a rough rule of thumb is it 1 Hp = 750 watts
so 3 Hp * 750 = 2250 watts (20 amps)
another rule is it takes 3 time the power to start a motor so you will need to supply 6750 watts (about 60 amps) to get the motor running.
You will also have to determing the runtime duty cycle of the motor. How long it needs to run compared to how long it can stay off once the air compressor has charged the air receiver.
You will then need to determine the frequency of starts which will be based on air consumption. How often will the compressor need to pump up the tank.
Then determine battery sizing /storage capacity to power the motor at night and cloudy days.
2006-12-10 04:35:54
·
answer #3
·
answered by MarkG 7
·
0⤊
0⤋
A horsepower is comparable to 746 watts, so a three hp motor could have the skill to be powered below secure state working situations by employing a 2238 watt inverter. even with the undeniable fact that, you're able to evaluate the surge cutting-edge required to start the motor while sizing the inverter. this relies upon on the form of motor used interior the air compressor. it somewhat is in all possibility why you haven't any longer been able to ability kit with nominally sized inverters interior the previous. In some vehicles, surge cutting-edge is 5-6 circumstances extra beneficial than the working cutting-edge. If it somewhat is real on your compressor, you have got problems with something below a 11kW to 14kWt inverter.
2016-12-30 05:28:48
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
Enough solar panels to generate around 2,235 J/s plus whatever else is lost in any conversion process you might require to convert the DC output of the solar panels to match the motors requirements (which will be, typically, 110V, 60 Hz, and a bit over 20 amps)
Doug
2006-12-10 04:16:03
·
answer #5
·
answered by doug_donaghue 7
·
0⤊
0⤋
Solar Power Design Manual - http://Solar.eudko.com/?qXj
2017-03-30 03:49:18
·
answer #6
·
answered by Judith 3
·
0⤊
0⤋
Sun is the source of energy.Most energy sources are ultimately derived from solar energy. Most governments offer several incentives to producers and users of alternative energy sources. Pleasevisit http://altenergy.in/
2006-12-10 23:21:30
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
You are going to need enough solar panels to roof your house....
2006-12-10 05:56:24
·
answer #8
·
answered by www.HaysEngineering.com 4
·
0⤊
0⤋
I don't know
2006-12-11 05:23:52
·
answer #9
·
answered by RaquelSolo 4
·
0⤊
0⤋