2006-12-09 17:17:50 · 6 answers · asked by lehanrony 3 in Science & Mathematics ➔ Engineering
amperage = wattage / voltage
Th
2006-12-09 17:20:34 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋
Depends on the power factor.
Amps = 500 W/ (Voltage * power factor)
If you don't konw the power factor, assume it is about 0.5 and plan for twice the current (amps) compared to just taking watts/volts.
EDIT: If you mean "bulb" and not "bull" then it is just 500 W divided by the voltage (assume it is 110 V, but check that its not something different). If you meant "bull" i assumed it was a like a mechanical bull with a motor, which would have a power factor less than one typically. A light bulb power factor is essentially = 1.
2006-12-09 17:25:44 · answer #2 · answered by Anonymous · 0⤊ 1⤋
500 Watts = 500 VA = 5 amps @ 100 volts. How many volts do you have?
2006-12-09 17:26:24 · answer #3 · answered by know_it_all_NOT 3 · 0⤊ 0⤋
15
2006-12-09 17:26:19 · answer #4 · answered by Miss Piggy 1 · 0⤊ 1⤋
Take your test on your own instead of getting on the internet and asking these types of questions!
2006-12-10 01:39:07 · answer #5 · answered by JoeSalsa 2 · 0⤊ 0⤋
this will depend on the voltage on the bulb
now you can solve
where
p=watts
e=volts
i=amps
e/p=i
2006-12-10 02:55:55 · answer #6 · answered by macgyver 1 · 0⤊ 0⤋