3 guys went in a hotel room that cost $30.00 they split the cost evenly, when finding out the hot water didn't work they recieved $5.00 back for the manager, the bell hop brought it to them but took $2.00 so each guy got $1 back, So they each payed $9. It 3 times 9 is 27 then add 2 that the bell hop took that is only $29.00 what happen to the other $1?
2006-12-08 06:15:28 · 4 answers · asked by Anonymous in Entertainment & Music ➔ Jokes & Riddles
The facts in this riddle are clear: There is an initial $30 charge. It should have been $25, so $5 must be returned and accounted for. $3 is given to the 3 friends, $2 is kept by the bellhop - there you have the $5. The trick to this riddle is that the addition and subtraction are done at the wrong times to misdirect your thinking - and quite successfully for most. Each of the 3 friends did indeed pay $9, not $10, and as far as the friends are concerned, they paid $27 for the night. But we know that the clerk will tell us that they were charged only $25 and when you add the $3 returned with the $2 kept by the bellhop, you come up with $30.
=)
2006-12-08 06:20:46 · answer #1 · answered by §èxÿtà mmý ® 5 · 1⤊ 0⤋
A classic.
This violates basic accounting principles, that's why it doesn't add up this way. It's tough to spot because it's very cleverly written and offers a seemingly logical (but wrong) recount of where the $ went.
$25 went to the hotel, not $27. So...$25 went to the hotel, $3 went back to the guys and $2 went to the bellhop.
2006-12-08 14:33:29 · answer #2 · answered by listen68 3 · 0⤊ 0⤋
Well, I dunno! The bell hop should have just kept the whole $5 then we wouldn't have this problem. So what's the answer?
2006-12-08 14:26:25 · answer #3 · answered by texasblueslady 3 · 0⤊ 0⤋
quite the conundrum we have here! Where did it go or where did it come from?
2006-12-08 14:29:48 · answer #4 · answered by KTINA 3 · 0⤊ 0⤋