I know a 40" wide screen has the same viewing area as a regular 32"
But what is the formula to figure it out so I can compare other sizes?
2006-12-07 09:12:09 · 4 answers · asked by 5ladderjob 3 in Consumer Electronics ➔ TVs
Try this document (it's a PDF so you may need to download adobe acrobat) - it shows how to compare the sizes of the various formats and calculate optimum viewing distance to size....
2006-12-07 09:27:16 · answer #1 · answered by jbtascam 5 · 1⤊ 0⤋
Just to clarify something it appears others missed. Screen size is measure on the diagnal.
The overall viewing area is not the same. The 40" 16:9 will have 700 sqin of screen where the 32" tv will have 475 sqin. What is common between the two is the screen height. So a standard definition (4:3) signal or show on the 40" HDTV will be the same size as a regular 32" tv not including the black bars shown on the side of your 4:3 image.
The video guru thing is helpful. His Calc reference http://www.htmart.com/pages.php?pageid=1 is helpful, too bad they don't show the comparison.
2006-12-07 18:36:43 · answer #2 · answered by Brian V 1 · 0⤊ 0⤋
4:3 is the ratio just like 16:9 is the ratio.
meaning. if the tv is 32" high it is then 24" long if the ratio were 4:4 the t.v. would be 32"high by 32" long(a square) if it were 4:2 it would be 32" by 16"
2006-12-07 17:26:31 · answer #3 · answered by pooteo1 3 · 1⤊ 0⤋
what you do is get a tape measure and mesure the width by height
this is simple the other guys are just nerds trying to sound smart
multiply both get answer, then your answer is in your hands
2006-12-07 18:04:19 · answer #4 · answered by Anonymous · 0⤊ 2⤋