assume concrete weighs 150 pounds per cubic foot.
2006-12-07 04:16:46 · 14 answers · asked by scoobydoocsi 1 in Science & Mathematics ➔ Engineering
12,500 lbs
2006-12-07 04:19:28 · answer #1 · answered by aficionado210 2 · 1⤊ 0⤋
12,375 give or take
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25' x 5' x .66'(8 inches is 2/3 of a foot) x 150 per cubic
2006-12-07 04:19:12 · answer #2 · answered by FRANKFUSS 6 · 0⤊ 0⤋
Geez.
Nice answers.
OK, get the volume first, keeping all units in feet.
25 X 5 X (8/12) = 83.33 cubic feet.
Weight = 83.33 X 150 = 12,500 lbs.
Crack a book, man.
2006-12-07 04:21:58 · answer #3 · answered by Boatman 3 · 0⤊ 0⤋
safe building 6 thick concrete roof 25 feet 16 feet supporting beams
2016-05-23 03:47:51 · answer #4 · answered by ? 4 · 0⤊ 0⤋
8 inches => 8/12 = 0.66667 feet
25 feet * 5 feet * 0.6667 ft = 83.333 cubic feet
83.333 cubic feet * 150 pounds/cubic foot = 12,500 pounds
Hope this helps!
2006-12-07 04:21:25 · answer #5 · answered by cfpops 5 · 0⤊ 0⤋
25 X 5 = AREA 125 SQ FT.
8 X 19.2 = 153.6
19.2 X 125 SQ FT = 2400 Bearing in mind that 3.6 X 125 has to be deducted
3.6 X 125 = 450 divide x 3.6 = 125 - 2400 = 2275 pounds
2006-12-07 04:39:25 · answer #6 · answered by Why cant i read my daily Emails? 3 · 0⤊ 0⤋
25 * 5 * 8 * 150 = 150 000 pounds
2006-12-07 04:19:02 · answer #7 · answered by DanE 7 · 0⤊ 1⤋
your wall dimensions
= 25*5*0.7
=87.5 cubic feet
thus assumed weight = 87.5*150 = 13125 pounds
(8 inches = approx 0.7 feet)
2006-12-07 04:21:47 · answer #8 · answered by Anonymous · 0⤊ 0⤋
83.3 cubic feet x 150 = 12,500 pounds
2006-12-07 04:20:16 · answer #9 · answered by parrotjohn2001 7 · 0⤊ 0⤋
depends on the type of concrete . . . more information is needed to answer this.
2006-12-07 04:18:56 · answer #10 · answered by kira217 2 · 0⤊ 1⤋
I'm guessing pretty freakin heavy!
2006-12-07 04:25:01 · answer #11 · answered by Anonymous · 0⤊ 0⤋