2006-12-06 08:33:42 · 6 answers · asked by peace 1 in Cars & Transportation ➔ Car Makes ➔ Nissan
An Absolute maxima does not exist for this function unless you are restricting x in a range and not just x> 0.
Just visualize this. The ln(x) function begins to plateau out as x get larger and larger, the increment in x won't change the ln(x) function a lot, but there is no way to bound the function f(x) = x.
To prove this, simply take the first derivitive and set f'(x) = 0 to determine if there is a point where the slope = 0
f'(x) = 11 + 2x (1/x) + lnx (2) = 13 + 2 lnx
The slope = 0 at
0 = 13 + 2lnx
Simplify
x = e^(-13/2) (Possible maximum/minimum) (approx 0.0015)
Test slopes around this point.
f'(.0001) = Negative value
f'(e) = 15 = Positive value
So x = e^(-13/2) is a minimum value (slope changing from negative to positive around this point). This are no other slope changes so there is no absolute maxima unless you give end points to x
2006-12-06 09:23:51 · answer #1 · answered by hsueh010 7 · 0⤊ 0⤋
Ah, a science joke. Nice try.
+2
2006-12-06 08:41:12 · answer #2 · answered by sethle99 5 · 0⤊ 1⤋
Find the maximum yourself.
2006-12-06 10:09:27 · answer #3 · answered by Anonymous · 0⤊ 1⤋
find it youself and stay off the drugs
2006-12-06 08:36:12 · answer #4 · answered by max p 1 · 0⤊ 1⤋
my brain hurts and my eyes are bleeding
2006-12-07 21:24:28 · answer #5 · answered by Anonymous · 0⤊ 1⤋
???? THE POWER OF CRIES REPELS YOU?!?!?!?!
2006-12-06 12:26:46 · answer #6 · answered by Anonymous · 0⤊ 1⤋