If u = yz, v = zx, w = xy and f is a function of x,y,z and thus of u,v,w
How do I show that x (jf/jx) = v (jf/jv)+w(jf/jw)
2006-12-06 06:50:16 · 5 answers · asked by tycho1a 1 in Science & Mathematics ➔ Engineering
I will use d for derivatives:
df/dx = df/dv dv/dx + df/dw dw/dx + df/du du/dx = z df/dv + y df/dw + 0 df/du (since u is independent of x).
Therefore: x df/dx = xz df/dv + xy df/dw = v df/dv + w df/dw.
2006-12-06 07:11:23 · answer #1 · answered by fernando_007 6 · 0⤊ 0⤋
w=x=44
you can show it because 44-j>6+4=w-x=f+x=j
and the inverse.
2006-12-06 14:53:22 · answer #2 · answered by killer boot 5 · 1⤊ 0⤋
NO, but I like all those funny little symbols.
2006-12-06 15:03:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
ummmm i dont no im sorry
2006-12-06 14:53:07 · answer #4 · answered by Sophie B 2 · 0⤊ 1⤋
I am sure someone can....
2006-12-06 14:52:46 · answer #5 · answered by Anonymous · 0⤊ 2⤋