go to myspace and set up a page.. Im sure u can find one on thier.. just any of the sites.. another one would be mate1.com or yahoo personals is another..
2006-12-06 04:25:26
·
answer #1
·
answered by blue eyes 3
·
0⤊
0⤋
This isn't a friggen dating service. Try match.com, craigslist, or some other service to get what you're looking for. Yahoo has it's own personals service also.
Also, since you're "in a relationship", shouldn't you break that off BEFORE you get someone new? Or is this a situation where, you're significant other is "abusive and self centered" because you're a gold digger looking for a hand out...and now you're stuck not being able to leave because your a loser?
2006-12-06 04:00:46
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
You are gay with 2 kids. I wonder how that happened? Sorry to hear that you wish to leave your partner good luck finding someone. But i definitly think you are looking in the wrong place, I really hope everything works out for you. GOOD LUCK!!!
2006-12-06 04:02:30
·
answer #3
·
answered by Nicolette G 2
·
0⤊
0⤋
You should try Yahoo! personals. You would have a better chance of finding someone there, than here on Yahoo answers.
2006-12-06 03:58:19
·
answer #4
·
answered by lildiesel2001 2
·
1⤊
0⤋
oh my god ...i am on the wrong site ! i thought this was Yahoo Q & A's....but maybe it is interacial/gay dating service....lol...good luck with that, but you need to go to Yahoo Personals for better responses....
2006-12-06 04:03:08
·
answer #5
·
answered by beachnut222000 4
·
0⤊
0⤋
check out okcupid.com ringo.com or even get a myspace.. good luck!
2006-12-06 03:57:45
·
answer #6
·
answered by yourmygoodfeeling 3
·
0⤊
0⤋
why don't you try a local dating site?
2006-12-06 03:58:55
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
good luck with that-we all got our problems
2006-12-06 03:57:36
·
answer #8
·
answered by Anonymous
·
0⤊
1⤋
sorry for the kids.
2006-12-06 03:58:43
·
answer #9
·
answered by Anonymous
·
0⤊
1⤋
try craigslist, not yahoo! answers.
2006-12-06 03:58:40
·
answer #10
·
answered by ? 5
·
1⤊
0⤋