what is the angular frequency of of pulsating dc that is obtained after rectifying a sine wave...
2006-12-06 02:47:02 · 3 answers · asked by narendrakm_2005 1 in Science & Mathematics ➔ Engineering
I assume you mean full-wave rectification. Ignoring the voltage drop in the diodes, the equation is the absolute value of the sinusoidal waveform.
V = | sin ωt |
where ω = 2π f
The Fourier expansion for this rectified waveform consists of even harmonics of the original sine wave. In power supplies, this makes the filtering of the rectified voltage somewhat easier, because the lowest frequency is twice that of the original frequency. For a 60 Hz single phase power, the filter sees a 120 Hz waveform. If you've got three phase power and a three phase full-wave rectifier, the filter sees a 360 Hz waveform. If your system is airborne, where three phase 400 Hz power is commonly available, the filter sees a 2400 Hz waveform. The advantage is that the higher the frequency, the smaller (and lighter weight) you can make the filter.
2006-12-06 03:00:24 · answer #1 · answered by Tech Dude 5 · 0⤊ 0⤋
ABS(sin(x)) is the rectified wave. The absolute value of the input is the rectified (assuming a full bridge rectifier). If its not a full bridge (basically just 1 diode, rather then the 4 in diamond shape) then its a piecewise function of sin(x) when sin(x)>0 and 0 when sin(x)<0.
The angular frequency remains the same as the non rectified I believe.
2006-12-06 02:52:24 · answer #2 · answered by merlin692 2 · 0⤊ 0⤋
A stabilizer in simple terms switches faucets on an autotransformer to maintain a nominal output. It would not rectify or have substantial filtering ability previous filtering for line noise.
2016-12-13 03:51:35 · answer #3 · answered by ? 3 · 0⤊ 0⤋