What are the odds of rolling three dice and the outcome is three numbers in a row?

Question

for example the outcome is a 1, 2, and a 3.

Answer 1

With 3 dice there are 216 combinations (6 cubed), regardless whether the dice are thrown one at a time or simultaneously.
Of these, there are 6 combinations that create 1,2,3, namely:1,2,3, and 1,3,2 and 2,1,3 and 2,3,1 and 3,1,2 and 3,2,1. The same goes for 2,3,4 and 3,4,5 and 4,5,6.
6 combinations for each of 4 results = 24 combinations out of a total of 216. Therefore the odds of getting what you asked for are:

1 in 9

Answer 2

There ae 6 faces to a die.
So the first time you can get any number.
The second time you there's only one choice you want, so you have one out of 6 possibilities.
The third time you there's only one choice you want also, so you have one out of 6 possibilities again.
This means that you have (1/6)x(1/6)=1/36 chance
That is if you accept that 5-6-1 are in a row.
If not, then for the first trow you have only three outcomes (1-2-3 only) out of 6 (so 1 out of 2 chances) that you want, and that brings down your chance from one out of 36 to one out of 72.

Answer 3

kihela is wrong...
if u roll a 4 first, ur second die can be a 5 or 3, so its not one possibility

possible combinations are:
1,2,3
2,3,4
3,4,5
4,5,6

4 times 0.167 to the power of 3 is the answer
which is 0.0186

btw he said rolling 3 dice he didnt mention rolling one at a time

Answer 4

Darryl above me is spot on. I don't play dice, but I am an avid poker player. His calculations are accurate.

Answer 5

depends how many numbers are on each dice?