2006-12-05 08:59:20 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
In a simple Op Amp integrator, the voltage on the capacitor is equal to the output voltage. Since the output voltage is the integral of the input voltage, that is the same as the waveform on the capacitor:
If the input is constant voltage, output (and capacitor) voltage is a ramp
If input is a square wave with equal positive and negative hemi-cycles, the output will be a triangle wave.
If input is a sinewave, you will get a sinewave delayed 90 degrees.
If the average value of your input is not zero, the output will eventually saturate and you will get a constant voltage across the capacitor.
2006-12-05 12:11:12 · answer #1 · answered by Eng_helper 2 · 0⤊ 0⤋
It is a saw tooth wave form!
2006-12-05 17:03:35 · answer #2 · answered by JUAN FRAN$$$ 7 · 0⤊ 0⤋
Depends on the application, and on whether you are talking about the integrator's input or output.
2006-12-05 17:09:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋