what is oz/in torque if .5 oz of force is measured on a .827 radius?

1 ⤊

what is oz/in torque if .5 oz of force is measured on a .827 radius?

2006-12-05 06:48:27 · 2 answers · asked by joseph p 1 in Science & Mathematics ➔ Engineering

2 answers

First, torque is force times radius, not divided by radius. So it's oz-in not oz/in. And the answer is force times radius, .4135.

2006-12-05 06:51:12 · answer #1 · answered by kirchwey 7 · 1⤊ 0⤋

Your maximum torque would be, in this instance, radius times force, assuming you are going in a circle.
Torque after that would be decreasing , unless the force stays perpendicular to the radius.

2006-12-05 17:59:41 · answer #2 · answered by jito11rivera 3 · 0⤊ 0⤋