who can resolve this mysterious event?

Question

Once upon time there was a man working as a bus driver, that bus was of 100 passangers size.
He used to travell between nieghbouring cities, with fixed price for each type of passangers, as follows;
'' 5 dollars for man, 2.250 for woman, 50 cents for a child''.
once he was travelling, driving his bus with 100 passangers in,
(( 100 passangers of the three different types of passangers,(men, women, children).)), when the bus arrived to the station of the intended city, they got off the bus after having paid the driver the required price for each,
after a while, the driver wanted to know how much money he got, he counted the whole money and found that he got 100 dollars???
he wants to know how many man, woman, and child were there in the bus during that trip, ((as they were all 100 passangers))!!!!!!!!!!

FOR MORE DETAILS, CONTACT ME ON [e-mail]

Answer 1

there were 8 male adult passengers, 8 female adult passengers and 84 children. so 8 + 8 + 84 = 100, and 8*5 + 8*2.25 + 84*0.5 = 100. nice!

if you want the total number of people, then there were 9 male adults (8 male passengers + 1 male driver), 8 female adults and 84 children. i got it by trial & error. thanks for the brain exercise!

Answer 2

60 children were on the bus with 20 women and four men
60 x .50 = 30.00
20 x 2.50 = 50.00
4 x 5.00 = 20.00

total 100 dollars

Answer 3

4 men $20
16 women $40
80 children $40

Answer 4

4 men
16 women
80 kids
No details needed.

Answer 5

20 men, and the rest where dogs, being female and one being a puppy?
more details needed please