Please answer the following curcuit question......thank you?

Question

An inductor with an inductance of 50 uH passes a current of 20mA when its terminal voltage is 6.3 V. Calculate the frequency of the AC supply.

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Answer 1

What he said.

The total impedance is simply

Z = voltage/current or 6.3/0.020 = 315 ohms

and the Impedance = 2*pi*F*L or:

315 = 6.284*0.000050*F

50.127 = 0.000050F

1,002,546 Hz. or approx. 1 MHz.

Answer 2

Z=V/I=2*pi*f*L

f=V/(I*L*2Ipi)=1 MHz