sine wave -power?

0 ⤊

how do you calculate the power of a sine wave

2006-12-02 22:35:07 · 3 answers · asked by jackal_04 1 in Science & Mathematics ➔ Engineering

3 answers

If v = Vsinωt
and i = Isinωt
then p = VIsin^2ωt = VI/2)(1-cos(2ωt))
..... ..... ...... ..... 2π
P = (VI/2)(1/2π)∫(1-cos(2ωt))dωt =
...... ..... ..... ..... 0
..... ..... ...... ..... ..... ..... ..... ..... .. 2π
P = (VI/2)(1/2π)[ωt + (1/2)sin(2ωt)]| =
..... ..... ..... ..... ..... ..... ..... ..... ..... 0
P = (VI/2)(1/2π)[2π - 0 + 0 - 0]
P(avg) = (1/2)VI

Note: V and I here are the maximum values. If rms values are used, P(avg) = V(rms)I(rms)

2006-12-02 23:15:27 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋

sine then the wave

2006-12-03 06:39:39 · answer #2 · answered by mariefel q 3 · 0⤊ 0⤋

use rms values and P=V.I

2006-12-03 16:53:02 · answer #3 · answered by Mark G 2 · 0⤊ 0⤋