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2006-12-02 17:59:18 · 2 answers · asked by qwerty2143 2 in Science & Mathematics Engineering

Sorry, guys.

This was meant for the Nilitary category.

2006-12-02 18:08:33 · update #1

2 answers

Probably less than 2 pounds of force:
http://www.fas.org/man/dod-101/sys/land/m67.htm

2006-12-02 19:01:54 · answer #1 · answered by arbiter007 6 · 0 0

The M67 grenade is a fragmentation hand grenade used by the US armed forces. It replaces the M61 grenade used during Vietnam and the older MK2 "pineapple" grenade used since World War II.

The M67 can be thrown about 40 meters by the average soldier. It has a 3 to 5 second fuse that ignites explosives packed inside a round body. Shrapnel is provided by the grenade casing, and produces a casualty radius of 15 meters, with a fatality radius of 5 meters, though some fragments can disperse as far out as 230 meters. The arming mechanism is typical of modern grenades: to arm the device, pull the pin; to ignite the fuse, release the safety lever, commonly known as the "spoon".

2006-12-03 03:46:40 · answer #2 · answered by Mikhil M 2 · 0 1

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