Calculate the volume of cylinders with diameters of 4in., 4.5in. and 4.375in. then subtract the volume of the 4in. cylinder from the other two. I got 1.35 times as much material for the larger pipe.
2006-12-02 06:20:40
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answer #1
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answered by er.doctor 2
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The outside diameters of the two pipes are 4 3/4 inches and 5 inches.
Area of a circle = [πd^2]/4.
Area of a 4 3/4" O.D. Pipe = [π(19/4)^2]/4 - [π(16/4)^2]/4
Area of a 5" O.D. Pipe = [π(20/4)^2]/4 - [π(16/4)^2]/4
Additional material = [π(20/4)^2]/4 - [π(19/4)^2]/4
As a percentage: {[π(20/4)^2]/4 - [π(19/4)^2]/4} / {[π(19/4)^2]/4 - [π(16/4)^2]/4}
Simplifying: (20^2-19^2)/(19^2-16^2) = 39/105 = 37.1%
37.1% more material is needed to make a 4" I.D. pipe with a 1/2" wall.
2006-12-02 07:14:04
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answer #2
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answered by Tech Dude 5
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now we assume that we have two cpipes , one inside the other , the outer dimeter have 34/8 dimeter (4+1/4) inch , and the inner pipe have 35/8 inch diameter (4+3/8) so for 1 meter o pipe we need
π(34/8-35/8)^2
=0.015625π inch^3
2006-12-02 06:22:24
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answer #3
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answered by manofnight12 2
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2016-12-10 20:27:52
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answer #4
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answered by lot 4
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