2006-12-02 01:51:42 · 7 answers · asked by marlon latorre 1 in Sports ➔ Boxing
Marquez had a chance for a rematch but he blew it. He wanted more money. Pacman doesn't need Marquez. Marquez need Pacman.
2006-12-02 03:36:35 · answer #1 · answered by tyrone b 6 · 0⤊ 1⤋
No need.
It is not a secret that the old, aged, prehistoric judge Burt Clements threw a 10-7 on what supposed to be a 10-6 round for Pacquiao on the first round.
We all know Pacquiao was a deadly lefty before and he have just developed a killer right now which was absent in his Marquez fight.
Right or left, if this fight pushes through, Pacquiao will win via Marquez RIP.
2006-12-02 19:57:35 · answer #2 · answered by josh_tadena 3 · 1⤊ 1⤋
Marlon ~
The "Pacman" claims it was because Juan Manuel out-priced himself, Marquez was asking for a 60/40 split in favor of Manny, plus a fraction of PPV sales. Manny and his team turned down Marquez flat ans said "That Marquez wasn't the draw, Manny is" they never went back to the table after that.
I believe it's a lot like my man Brent wrote to you. There's a strong possibility that Marquez would take Manny's title in a rematch, heck, Manny had the kid down three times in the first round and couldn't put him away and alls Manny got was a Draw? Doesn't sound like Manny wants to fight a kid who's in his prime that can take his title to me.
Thanks for the question Marlon.
2006-12-02 13:23:57 · answer #3 · answered by Santana D 6 · 1⤊ 1⤋
Because Marquez gave Manny (with the exception of the first round) all he could handle. Styles make fights, Manny has trouble with Marquez's style.
2006-12-02 02:02:45 · answer #4 · answered by Brent 5 · 2⤊ 0⤋
because pacman gonna hit marquez at his chest again
2006-12-03 10:11:56 · answer #5 · answered by skyfrc 1 · 0⤊ 0⤋
because Marquez is gay and if ever they fight, Pacman's gonna whoop his ass!!!
2006-12-03 22:24:24 · answer #6 · answered by general 1 · 0⤊ 0⤋
better yet, why don't Donkey Kong and Rico Suave have a rematch...ya heard me?!
2006-12-02 01:53:21 · answer #7 · answered by Anonymous · 0⤊ 0⤋