Black fur in mice (B) is dominant to brown fur (b). Short tails (T) are dominant to long tails (t). What fraction of the progeny of the cross BbTt × bbtt will have brown fur and long tails?
A. 0%
B.25%
C.50%
D. 75%
2006-12-01 22:43:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Biology
.25%
2006-12-01 22:45:02 · answer #1 · answered by jeete 1 · 0⤊ 0⤋
They are all saying 25% but they aren't crossing BbTt with bbtt.
It's BbTt, BbTt, bbtt, bbtt. So I'd go with 50%
2006-12-01 23:00:37 · answer #2 · answered by sailortinkitty 6 · 1⤊ 0⤋
B. 25%
2006-12-01 22:48:19 · answer #3 · answered by Anonymous · 0⤊ 1⤋
B. 25%
2006-12-01 22:45:55 · answer #4 · answered by rishi_is_awake 3 · 0⤊ 1⤋
X | BT Bt bT bt
__|______________
bt | BT Bt bT bt
__|______________
bt | BT Bt bT bt
__|______________
bt | BT Bt bT bt
__|______________
bt | BT Bt bT bt
brown fur and long tails = bt is 4 boxes out of 16 aka 25%
a better table http://www.accessexcellence.org/RC/VL/GG/recessive.html
but htat's the idea =)
2006-12-01 23:05:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋