the atomic number of carbon is 6...
therefore the configuration would be
1s^2 2s^2 2p^2
2006-12-01 22:33:57
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answer #1
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answered by sue 2
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The electronic configuration of the carbon atom, ls22s22p2, is responsible for the covalent bonding found in all compounds containing carbon. Unlike those elements at the extremes of the periodic table, carbon is neither electronegative like the halogens nor electropositive like the alkali metals. Because it is located in the middle group (IV A) of the representative elements, carbon, with four valence electrons, is not able to participate in ionic bonding. That is, with only six protons and six electrons in the neutral atom, carbon cannot afford to gain or to lose four electrons in order to become C-4(ls22s22p6) or C+4(ls22s02p0) in an ionic compound. Such a surplus of charge on such a small species is not stable. However, carbon is ideally suited for the electron sharing observed in covalent bonding; carbon achieves an octet by sharing its four valence electrons with four valence electrons from other atoms. Through this bonding, carbon obtains the ls22s22p6 noble gas configuration of neon.
2006-12-02 06:12:49
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answer #2
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answered by mallimalar_2000 7
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I'm sorry, this answer doesn't directly address your question. However, have you ever thought about the concept that a diamond, made entirely (in theory) of carbon-carbon bonds in a lattice that makes it the hardest substance on Earth is given by lovers to their beloved to mark the act of marriage between those beings on this planet who are perhaps the highest form of carbon-based life on the planet (humans)--notwithstanding some of our more baneful evils like the infliction of unjust captivity, the promulgation of unbridled capitalism and the instigation of hypocritical wars?
2006-12-02 05:55:03
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answer #3
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answered by Mark 3
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Carbon Z=6
2 electrons on inner shell K we write this 1s2
4 electrons on the shell L as follows
2 electrons on the subshell 2s we write 2s2
2 electrons on the subshell 2p we write 2p2
we write 1s2 2s2 2p2
The number of electrons on the subshell should be written in exponant
2006-12-02 05:52:55
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answer #4
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answered by maussy 7
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1s^2 2s^2 2p^2
2006-12-02 05:51:15
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answer #5
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answered by Anonymous
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