By the answers of others, you seem to annoy, as well as stimulate the mind. Friend.
Let's start with a definition of an "odd" number. It is usually defined as a number which can only be divided evenly, with no remainder, by itself and by 1. Is this correct?
For if this is so, then your silly problem is easily solved, in many ways, many numbers.....
Because 2 can only be divided by itself and 1, evenly.
**Therefore, 2 is an odd number.**
Let's solve your little problem, the math one that is.. getting your first date with a real girl, dude, you are on your own, still!!
How About:
41+7+3+3+2+1+1+1+1= 60.
I believe that's Best Answer Quality, don't You? Really?
2006-12-01 21:03:42
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answer #1
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answered by Anonymous
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1+3+5+7+9+11+9+7+5=60
2006-12-04 00:09:37
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answer #2
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answered by arpita 5
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1+3+5+7+9+11+5+7+9=60
2006-12-02 04:33:34
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answer #3
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answered by raj 7
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5+5+5+5+5+5+5+15+15-5. I used 9 positive numbers. You never stated how many total number of numbers I needed, just that I needed to use 9 odd numbers.
2006-12-02 04:36:45
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answer #4
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answered by gregory_dittman 7
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hello
Do you what is the result when you add two
odd numbers?
When you add two numbers the result is a even number
ex.3+5=8
hence when you want a even number by adding the odd numbers , you must have even number of odd numbers.
in your question you are asking to use 9 odd numbers but you want the result to be even.is it possible,think about it
since 60 is a even,the answer for your question does not exist.
We can answer your question only when you and I accept ,'0' is a positive and also odd number but 0 is neither positive nor negative also 0 is considered to be even.
hence i think there is no answer for your question
2006-12-02 05:57:57
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answer #5
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answered by khanij kumar s g 1
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an odd number of odd numbers added together will be an odd number. 60 is even.
2006-12-02 04:28:47
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answer #6
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answered by MooseBoys 6
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1+3+5+7+9+13+15+7=60
is that what u need
2006-12-02 11:51:07
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answer #7
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answered by Hemali 2
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Question invalid. 60 is even already, it's not possible.
2006-12-02 04:27:48
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answer #8
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answered by prabato 3
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Please stop posting the same problem.
2006-12-02 04:24:07
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answer #9
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answered by Anonymous
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