HCl provided is 2M,
limewater contains 1g dm-3 CaOH
2006-12-01 19:53:19 · 2 answers · asked by cinnamonstar123 2 in Science & Mathematics ➔ Chemistry
The Mr of Ca(OH)2 is 74, so your solution of lime-water is 1/74 M.
You want the HCl to be about twice as concentrated (2:1 mole ratio in the reaction) so it should be about 1/30 M
1/20 M would so, so take 5cm3 of your HCl in a pipette, and dilute it up to 100cm3 in a volumetric flask.
2006-12-01 20:09:14 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
Not CaOH but Ca(OH)2.
This has a molecular mass of 74 so the molarity of the solution is 1/74 . OK to use an approximation here so this could be 1/80.
Soince 2 moles of HCl reacts with 1 mole of the hydroxide for simililar volumes of liquid to react the HCl must be 1/40
The original acid must be diluted 80 times (1cm3 becomes 80 cm3)
A good option would be to use 5 cm3 to make 400 cm3 of diluted acid.
2006-12-03 14:21:19 · answer #2 · answered by lykovetos 5 · 0⤊ 0⤋