2006-12-01 17:53:19 · 5 answers · asked by Hilary 1 in Science & Mathematics ➔ Physics
1. Average acceleration = 1.1958 meter per square second.
2. Speed = 26.7857 meter per second.
Formula used for Sl. no.1 : S = ut +1/2 a (t)exp2
Formula used for Sl. No. 2 : v = u + at
2006-12-01 18:12:21 · answer #1 · answered by Rohan Gupta 2 · 0⤊ 0⤋
A= acceleration
V (o)= initial velocity
V (f)= Final velocity
T= time
V (o)= 0 because the car starts from rest.
V (f)= 300/22.4
V (f)=13.4m/s^2
A= V(f)- V(o)/Time taken(22.4s)
A= 13.4-0/22.4
A=0.59m/s^2
2006-12-01 21:36:27 · answer #2 · answered by edik 4 · 0⤊ 0⤋
Speed=Distance/time
=300/22.4
=13.393 m/s
Average acc.=(final speed-initial speed)/time
=(13.393-0)/22.4
=0.598 m/s^2
2006-12-01 18:05:24 · answer #3 · answered by Anonymous · 0⤊ 0⤋
A=1.19
S=26.8
2006-12-01 20:32:08 · answer #4 · answered by praveen_silicon 2 · 0⤊ 0⤋
avgV= 300/22.4 = 13.39 m/s
13.39/22.4 = .59879 m/s^2
im pretty sure thats right
2006-12-01 18:09:49 · answer #5 · answered by Anonymous · 0⤊ 0⤋