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An air bubble is initially entrapped in the buret for the standardization of the sodium hydroxide solution. However, during the titration the air bubble is passed from the buret. Will the reported molar concentration of the sodium hydroxide be reported as too high, too low, or unchanged as a result? Explain.

2006-12-01 14:06:35 · 4 answers · asked by ZG786 1 in Science & Mathematics Chemistry

4 answers

The reported molar concentration will be too high.

Since the air bubble in the Beret is occupying an unknown volume, when it passes from the Beret your data will show that you needed more sodium hydroxide to titrate then actually required.

For example, if you had 50mL in the Beret with the air bubble, and at the end of titration you have 35mL, you would conclude that you used 15mL to complete titration. BUT, you really would have only used 14 or 13 mL of sodium hydroxide because as the bubble escaped it made your data look like the solution was coming out, but you know that only air was passing through.

So you will believe that the concentration that you have in the Beret is larger than what it actually is because you needed more of it to titrate it.

Just in case you don't know what titration is, to find the concentration of a solution, you take a controlled amount of whatever you want to find the concentration of and empty it into a beaker filled with an indicator. When the indicator changes color that indicates a neutralization, you can use equations to find out exactly what the concentration is based on how much solution was needed to neutralize the indicator.

2006-12-01 14:17:38 · answer #1 · answered by Nick 1 · 1 0

Reported concentration of NaOH will be lower than the actual result.Since the volume consumed will be greater than the actual volume and since the titre value is taken in the denominator in the calculation of strength of sodium hydroxide, we'll get a lower value than the actual result.

2006-12-01 17:44:48 · answer #2 · answered by pal 1 · 0 0

Depend on the depth and the rate of expansion to surface under most circumstances it will remain the same.

2006-12-01 14:17:24 · answer #3 · answered by matt v 3 · 0 0

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2006-12-01 14:19:18 · answer #4 · answered by efj g 1 · 0 0

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