If 27% of the bases in a certain segment of DNA were adenine, what would be the percentage of (Hint: Which base will have the same percentage as adenine):
a)thymine -
b)cytosine -
c)guanine -
2006-12-01 12:49:43 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Biology
You can only answer this question if you are told that the DNA segment is double stranded. If it is not double stranded, all bets are off.
2006-12-01 13:03:34 · answer #1 · answered by Anonymous · 1⤊ 0⤋
adenine pairs with thymine, so thymine would also be 27%.
So A + T = 54%.
The remaining bases, C and G would be in equal proportions and make up the other 46%. (23% each)
a) 27%
b) 23%
c) 23%
2006-12-01 21:01:43 · answer #2 · answered by ♪ ♫ ☮ NYbron ☮ ♪ ♫ 6 · 0⤊ 0⤋
You know that in DNA, adenine pairs with thymine, so there must be 27% thymine. The remainder of the 46% is split up equally between cytosine and guanine, since they exist as pairs; there is 23 %of each.
a) 27%
b) 23%
c) 23%
2006-12-01 20:58:43 · answer #3 · answered by Empress Sky 2 · 0⤊ 0⤋
a=t so 27% of t also and 27+27 is 54 so 100-54 is 46 so u know that 46 makes up the total for c and g. one half of 46 is 23 so there is 23 c and 23 g
2006-12-01 21:23:03 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I beleive it's called Chargaf rules where A=T and G=C (number of purines is equal to number of pyrimidines) so u would have 27%o thymine and 23% for cytosine and guanine
2006-12-01 21:07:08 · answer #5 · answered by jj 2 · 0⤊ 0⤋
A=T (27%)
A+T=54%
100%-54%=46%(C+G)
C=G(23%)
2006-12-01 23:37:59 · answer #6 · answered by hana7pink 1 · 0⤊ 0⤋