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Question

A U-tube of constant cross-sectional area, open to the atmosphere, is partially filled with a heavy liquid with density of 9.04 g/cm^3. A light liquid with density 2.01 g/cm^3 is then poured into both arms. If the difference in the height of the heavy liquid is 1.31 cm, determine the value of the difference in height of the light liquid hl (in units of cm).

Answer 1

The additional space occupied by the heavy liquid (1.31cm) reprsents a pressure difference of dh*1.31 cm. This must be balanced by the pressure of light liquid on the opposite side = dl*x cm Therefore
x= dh/dl 1.31cm dh=density of heavy liq, dl = density of light liq.