sry its al bunched up it wouldnt fit... plz help
2006-12-01 11:40:52 · 4 answers · asked by anonymous 2 in Science & Mathematics ➔ Mathematics
x = youngest brother's age
x + 4 = other brother's age
2(x + 4) = Anna's age
x + (x + 4) + 2(x + 4) = 32
x + x + 4 + 2x + 8 = 32
4x + 12 = 32
4x = 20
x = 5
x + 4 = 9
2(x + 4) = 18
ANSWER: Anna is 18 years old.
2006-12-01 11:46:51 · answer #1 · answered by Anonymous · 0⤊ 0⤋
OK, to solve this, set Anna's age to x
x = Anna's age
x/2 = brother 1's age
(x/2) - 4 = brother 2's age
Adding all three siblings ages together, you get:
x + (x/2) + (x/2) - 4 = 32
Solve for x:
2x - 4 = 32
2x = 36
x = 18
Since x = Anna's age, then she's 18.
Always double check by calculating the brother's ages, by plugging it back into the equations up top (brother 1's age is 9, brother 2's age is 5, 18 + 9 + 5 = 32! Correct)
2006-12-01 11:47:25 · answer #2 · answered by sep_n 3 · 0⤊ 0⤋
32 = 2 x + x + x -4
4x = 36 => x = 9
Anna = 2x = 18
Brother = x = 9
Other brother = x - 4 = 5
18+9+5 = 32
2006-12-01 11:46:07 · answer #3 · answered by Modus Operandi 6 · 0⤊ 0⤋
For future reference, please write the question in the "detailed" portion of yahoo questions so it will all fit.
Let B = age of Anna's brother.
Then 2B = age of Anna, and
B+4 = age of other brother
The sum of the ages is 32. Therefore,
B + 2B + B + 4 = 32.
Combine like terms,
4B + 4 = 32
4B = 28
B = 7
Therefore, Anna's brother is 7, Anna is 14, and the other brother is 11.
2006-12-01 11:48:45 · answer #4 · answered by Puggy 7 · 0⤊ 0⤋