A particular engine has a power output of 6.00 kW and an efficiency of 24.0%. Assume the engine expels 6500 J?

Question

(a) Find the energy absorbed in each cycle. in kJ
(b) Find the time required to complete each cycle. (s)

Answer 1

A very unclear question but here goes my try:
Assume the engine expels 6500 J AS HEAT PER CYCLE (assumed).
a) Energy absorbed is thermal energy input (assumed). Then the 6500 J shed as heat is 76% of the energy input, so energy input per cycle = 6500/.76=8552.6 J.
b) Energy output per cycle = 8552.6 - 6500 = 2052.6 J, so each cycle takes 2052.6 J/cycle divided by 6000 J/s = 0.3421 s/cycle.