leg² + leg² = hyp²
If the triangle is isosceles, the 2 legs are equal, so you have
2x² = hyp²
x√2 = hyp
x = hyp / √2
2006-12-01 11:14:52
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answer #1
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answered by Philo 7
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c^2 = b^2 + a^2, where c is the hypotenuse and a and b are the 'legs' as you call them.
Since its an isosceles right triangle, the legs are equal, so b = a
therefore c^2 = 2(a^2), so the leg length (a) = sqrt(c^2 / 2)
2006-12-01 19:15:48
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answer #2
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answered by xenrous 2
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since it is a rt triangle the angles are 45, 45, and 90.
in a right triangle sin 45 = opposite/hypotenuse therefore a side which are the same for an isosceles triangle is
side=hypotenuse * sin 45(.707)
remember soh cah toa
sin angle = opposite/ hypotenuse
cos angle = adjacent/ hypotenuse
tan angle = opposite/adjacent
2006-12-01 19:24:02
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answer #3
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answered by wayne 4
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c² = a² + b² --- Pythagorean Theorem
Since both legs are the same:
c² = a² + a²
c² = 2a² --- Square root of each side...
c = (â2)a
ANSWER: c = (â2)a --- where c is the hypotenuse, and a is the measure of the two identical legs)
2006-12-01 19:14:32
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answer #4
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answered by Anonymous
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It is also the pythagorean theorem, only with two sides set as equal since it is isoceles:
PYTHAGOREAN: a^2+b^2=c^2
A = B: a^2 + a^2 = c^2
SIMPLIFY: 2a^2 = c^2
Now simply plug in the known hypothenuse value, such as 8.
2a^2 = 8
a^2 = 4
a = 2
The length of the legs in this case is 2.
2006-12-01 19:18:04
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answer #5
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answered by John H 4
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leg squared + leg squared = hypotenuse squared or
2 leg squared = hypotenuse squared
2006-12-01 19:10:53
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answer #6
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answered by MollyMAM 6
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since it is isosceles, a=b so
h^2=a^2+a^2=2a^2
a=.5hâ2
2006-12-01 19:22:26
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answer #7
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answered by yupchagee 7
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