A cylinderical shaped metal rod is used to conduct heat. When the temperature at one end is 100 degree Celsius and at the other end is 20 degree Celsius, heat is transferred at a rate of 16 J/s. The rod is then stretched uniformly to twice its original length. If again it has ends at 100 degree Celsius and 20 degree Celsius, at what rate will heat be transferred between it ends?
The answers that are given to me are:
4 J/s
8 J/s
32 J/s
2 J/s
64 J/s
16 J/s
1 J/s
2006-12-01 10:31:07 · 2 answers · asked by jay s 1 in Science & Mathematics ➔ Physics
4 j/s
2006-12-03 09:56:53 · answer #1 · answered by master 1 · 0⤊ 0⤋
Heat conduction is directly related to the cross-sectional area thru which the heat flows (among other things). In the case of this rod, its decrease in area decreases its ability to conduct heat. Since the volume stayed the same, the stretching that doubled the length, halved the cross-sectional area. So the J/s will be half of what it was before.
2006-12-01 20:15:12 · answer #2 · answered by sojsail 7 · 0⤊ 0⤋