ffactor fully and need all step?

Question

1. 2x"3+10x square+8x
2. 4a"3-4a square - 48a
3. 2x"5-6x"4-36x"3

Answer 1

I'm going to rewrite your question in a more conventional way. Remember that we denote "to the power of" with the ^ symbol.

1. 2x^3 + 10x^2 + 8x

First, pull out the biggest factor. In this case, it's 2x. So we get
2x (x^2 + 5x + 4)

Now, we factor the quadratic normally.
2x (x + 4) (x + 1)

2. 4a^3 - 4a^2 - 48a

Biggest factor to pull out is 4a

4a(a^2 - a - 12)
4a(a - 4) (a + 3)

3. 2x^5 - 6x^4 - 36x^3

Biggest factor: 2x^3

2x^3 (x^2 - 3x - 18)
2x^3 (x - 6) (x + 3)

Answer 2

I think that this should be written
1.
2x^3+10x^2+8x = 2x*(x^2+5x+4)= 2x * (x+1) * (x+4)

2.
4a^3-4a^2-48a = 4a * (a^2-a-12) = 4a * (a-4) * (a+3)

3.
2x^5-6x^4-36x^3 = 2x^3 * (x^2-3x-18) = 2x^3 * (x+3) * (x-6)