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840

2006-12-01 07:38:30 · 5 answers · asked by Shelly H 2 in Science & Mathematics Mathematics

5 answers

2³*3*5*7

This is very simple, you ought to be able to do it on a calculator. Just divide by numbers that go into it evenly... with 840, it is obvious that it divides by 2 and 5; once you remove those factors, you are left with 21, which you ought to recognise as 3*7. Just write down each factor as you divide by it, and once you are done, you will have your prime factorization.

2006-12-01 07:40:07 · answer #1 · answered by computerguy103 6 · 1 0

Rule of thumb: if you add up all the digits and it is divisible by 3, then 3 is a prime factor. In this case, it's true.

840 = 3 x 280

Then you successively break down the big numbers. Note that 280 = 2 x 140

840 = 3 x 2 x 140

Now, break up 140

840 = 3 x 2 x 2 x 70

Now, break up 70

840 = 3 x 2 x 2 x 2 x 35

Now, break up 35. Note that 35 = 7 x 5

840 = 3 x 2 x 2 x 2 x 5 x 7

Now, put the prime factors into numerical order

840 = 2 x 2 x 2 x 3 x 5 x 7

That's it.

2006-12-01 15:42:09 · answer #2 · answered by Puggy 7 · 0 0

840=2^3*3*5*7

2006-12-01 15:41:06 · answer #3 · answered by yupchagee 7 · 0 0

two to the seccond power times three times five

2006-12-01 15:42:25 · answer #4 · answered by Anonymous · 0 0

2
2
2
5
3
7

2006-12-01 15:43:31 · answer #5 · answered by Sanjay C 1 · 0 0

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