2³*3*5*7
This is very simple, you ought to be able to do it on a calculator. Just divide by numbers that go into it evenly... with 840, it is obvious that it divides by 2 and 5; once you remove those factors, you are left with 21, which you ought to recognise as 3*7. Just write down each factor as you divide by it, and once you are done, you will have your prime factorization.
2006-12-01 07:40:07
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answer #1
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answered by computerguy103 6
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Rule of thumb: if you add up all the digits and it is divisible by 3, then 3 is a prime factor. In this case, it's true.
840 = 3 x 280
Then you successively break down the big numbers. Note that 280 = 2 x 140
840 = 3 x 2 x 140
Now, break up 140
840 = 3 x 2 x 2 x 70
Now, break up 70
840 = 3 x 2 x 2 x 2 x 35
Now, break up 35. Note that 35 = 7 x 5
840 = 3 x 2 x 2 x 2 x 5 x 7
Now, put the prime factors into numerical order
840 = 2 x 2 x 2 x 3 x 5 x 7
That's it.
2006-12-01 15:42:09
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answer #2
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answered by Puggy 7
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840=2^3*3*5*7
2006-12-01 15:41:06
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answer #3
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answered by yupchagee 7
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two to the seccond power times three times five
2006-12-01 15:42:25
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answer #4
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answered by Anonymous
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2
2
2
5
3
7
2006-12-01 15:43:31
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answer #5
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answered by Sanjay C 1
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