draw the acid catalyzed sn1 mechanism for the preparaion of diisopropyl ether?

Answer 1

For simplicity, let's say (CH3)2CH-OH is iPr-OH.

iPr-OH + H2SO4 ===> iPr-OH2+ ===> iPr+ + H2O

iPr+ + iPrOH ===> iPr-O^+H-iPr ===> iPr-O-iPr + H+

In that third line, the two iPr's are bonded to O. O is bonded to H, and the >O-H center is positively charged, ^+. So that's protonated diisopropyl ether.