X^2/3 + x^1/3 - 6 = 0
2006-12-01 07:07:00 · 10 answers · asked by Vincenzo 1 in Science & Mathematics ➔ Mathematics
That looks like ((X+3)*(X-2))^1/3 = 0
You should be able to get it from there.
2006-12-01 07:11:08 · answer #1 · answered by Jessica K 2 · 0⤊ 1⤋
x=3
2006-12-01 07:11:20 · answer #2 · answered by Jordan E 1 · 0⤊ 1⤋
Let x^1/3=t
Equation becomes:
t^2+t-6=0
=> t= -3 or t= 2
t= -3 => x^1/3= -3 => x= -27
t=2 => x^1/3=2 => x= 8
2006-12-01 07:13:03 · answer #3 · answered by Vu 2 · 2⤊ 0⤋
X^2/3 + x^1/3 - 6 = 0
(x^1/3+3)(x^1/3-2)=0
x^1/3=-3
x=-27
x^1/3=2
x=8
2006-12-01 07:37:01 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
x^(2/3) + x^(1/3) - 6 = 0
Let y = x^(1/3)
Therefore, y^2 + y - 6 = 0
Factorise : (y + 3)(y - 2) = 0
So, y = -3 or +2
If y = -3, then x^(1/3) = -3
Cube both sides to get : x = -27.
If y = +2, then x^(1/3) = +2.
Cube both sides to get : x = 8
The 2 solutions are x = -27 or x = 8.
2006-12-01 07:16:27 · answer #5 · answered by falzoon 7 · 0⤊ 0⤋
The first thing you have to do is multiply by the lowest common denominator. In this case, it's 3. So we get
x^2 + x - 18 = 0
Now, we solve for x. This isn't a factorable equation, so we have to use the quadratic formula.
x = (-1 +/- sqrt(1 - 4(-18)))/2
x = (-1 +/- sqrt(73))/2
So our two values are
x = (-1 + sqrt(73))/2 and
x=(-1 - sqrt(73))/2
2006-12-01 07:13:45 · answer #6 · answered by Puggy 7 · 0⤊ 1⤋
X(2/3) +X(1/3)-6=0
2X/3+X/3=6
2X+X=6(3)
3X=18
X=6
Answer:6
2006-12-01 07:13:48 · answer #7 · answered by Anonymous · 0⤊ 1⤋
x^1/3 + 3)(x^1/3 - 2) = 0
x^1/3 = -3, 2
x = -27, 8
2006-12-01 07:12:39 · answer #8 · answered by Helmut 7 · 0⤊ 1⤋
Vu got it right
2006-12-01 07:16:18 · answer #9 · answered by T 5 · 0⤊ 0⤋
turd
2006-12-01 07:14:06 · answer #10 · answered by Anonymous · 0⤊ 3⤋