Rationalize the Denominator?

Question

3
_________
3root of 2y

Answer 1

3/3srt2y(srt2y/srt2y)=3srt2y/6

Answer 2

So you want to rationalize

3/(3sqrt(2y))

Remember that using this limited interface, we usually denote fractions using /.

First off, the 3 on top and the 3 on bottom will cancel each other out, giving you

1/sqrt(2y)

A rule of thumb with mixing square roots and fractions is __you never want a radical on the bottom__ (radicals are square roots). This is no exception.

To get rid of it, you multiply the top and bottom by sqrt(2y), so it becomes

sqrt(2y)/[sqrt(2y)sqrt(2y)]

Remember that multiplying a square root by itself eliminates the square root, and you're left with

sqrt(2y)/2y

And that's it!

Answer 3

to rationalize the denominator u have to get rid of the cube root. so multiply the top and the bottom (numerator and denominator) by the cube root of 2y:

....3.............3root of 2y.....3 times (3root of 2y)
________ x ________ = _________________
3root of 2y...3root of 2y................2y

and that is your answer:

three times the cube root of 2y divided by 2y

Answer 4

If you are saying

3 divided by the cube root of 2y,

cube the entire expression gets

27 / 2y

Answer 5

3 / (2y)^(1/3)

Multiply numerator and
denominator by (2y)^(2/3).

This gives : 3(2y)^(2/3) / (2y).