During his career, Boras has negotiated more than $2 billion in contracts, netting him more than $100 million. He could retire anytime.
2006-12-01 06:06:07
·
answer #1
·
answered by Colin L 5
·
1⤊
0⤋
I don't know how much he makes since his salary is very much vague by his representation, but he usually takes around 10-20% of what his players makes in their current contract. You know he has the reputation of overvaluing his players and change the landscape of baseball that even Babe Ruth or others great could have imagine (A-Rod 10 year, 252 million is still the largest contract for a single athelte that doesn't include endorsements in the money figure). Every season, he figures to be a major player in baseball off-season and here are some of the clients that are FA now:
J.D. Drew
Eric Gagne
Barry Zito
Jeff Weaver
Greg Maddux
Daisuke Matsuzaka (still negotiating w/ Boston)
Besides A-Rod, here are some notable clients that are represented by Boras now who either has a big payday or about to see in the near future:
Rocco Baldelli
Carlos Beltran
Bruce Chen
Joe Crede
Johnny Damon
Stephen Drew
Prince Fielder
Matt Holliday
Andruw Jones
Scott Kazmir
Felipe Lopez
Rodrigo Lopez
Derek Lowe
Kevin Milwood
Magglio Ordonez
Corey Patterson
John Patterson
Anthony Reyes
Ivan Rodriguez
Kenny Rogers
Willy Taveras
Mark Teixeira
Jason Varitek
Jarrod Washburn
Jered Weaver
of course, Boras doesn't discriminate in getting some bad players as clients too:
Bobby Hill
Dan Kolb
Travis Lee
Kyle Lohse
Xaiver Nady
Chan Ho Park
Carlos Pena
Oliver Perez
Rey Sanchez
Scott Schoeneweis
Then there are the disgruntled players who didn't like the way that Boras handle the situation well:
Barry Bonds
Miguel Cabrera
Ramon Hernandez
Gary Sheffield
Carlos Zambrano
Of course I don't have the complete list because it requires at least one book to fill out all of his clients, past and present, to go along with millions in dollar figures he made with every MLB team he negotiated with, so its hard to see how much he makes because it's vague to tell at this point, since he is an power agent.
If you want the NFL equivalant of Boras, then look no further than Drew Rosenhaus, who's clients includes T.O. and Chad Johnson (oh boy!). Although Bill Duffy doesn't have the name sake of Boras or Rosenhaus, he is the power guy in the NBA, which his clients includes Yao Ming, Carmelo Anthony, and Steve Nash.
2006-12-01 09:56:20
·
answer #2
·
answered by mojo8983 5
·
1⤊
1⤋
Scott Boras is a multi-millionaire. Typically, a sports agent gets anywhere between 3-10% of the players contract.
2006-12-01 06:03:32
·
answer #3
·
answered by kcslammer13 3
·
0⤊
0⤋
The fact that we are living and breathing and able to do all these things. The fact that we are not rocks and some divine coincidence made use who we are instead of some inorganic atom. The fact we can give things worth. We can categorise. Its all beautiful, the sight, the sound, the feel, the emotion, the taste. Even pain. We can feel that not many other things can. Pain may be painful, but we can feel it just as we can feel happy. Its amazing really that out of all of this we can do these things. Although it seems to suck sometimes its still wonderful. random fact: if you shoot a rabbit, it doesnt know why it feels pain, it doesn't register that there is an explanation, it just knows it feels pain and as a reaction will run away, even if its dying. Shoot a human (even if they did not know what a gun was) it would realise its something launched, have some sort or knowledge of what to do and so on. I dont think this was relevant but its written now... But if youre looking for one reason it would definitely be pie.
2016-05-23 08:09:59
·
answer #4
·
answered by ? 4
·
0⤊
0⤋
Stinking filthy rich.
2006-12-01 06:09:16
·
answer #5
·
answered by Oz 7
·
0⤊
0⤋
a lot!! i'd say between 3 and 6 mil
2006-12-01 07:57:26
·
answer #6
·
answered by Larry 4
·
0⤊
0⤋
His last income tax filing showed he made 7.2 mil last year.
Coach
2006-12-01 06:04:10
·
answer #7
·
answered by Thanks for the Yahoo Jacket 7
·
0⤊
0⤋
A lot, and A lot.
2006-12-01 06:54:48
·
answer #8
·
answered by Jasper 1
·
0⤊
0⤋