// MultiLoad.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include
#include
#include
/*
Number of jobs - 4 to 7
Volume of jobs - 5 to 15
No of process - 3
Job units - 1 to 6
*/
int NoJ=4;//Number of jobs
float VoJ[4]={15,12,10,5};//Volume of jobs value min=5 max=15
float NoP[3][4]={{2,2,5,3},
{5,4,4,2},
{4,3,5,1}};//No of process
//int JU[6]=0;//Job units
float coeffxy[3];
float BLog[3]={6,10,15};
float time[3]={0,0,0};
float maxRatio=0.0;
int split=0,split1=0,split2=0;
float v=0.0;
float e1=BLog[0];
float e2=BLog[1];
float x,y;
float e3,e4;
float t3equ[3];
float e1x=0,e3x=0,e2y=0,e3y=0;
int twist=0;
float SolveEqution(float e1,float e2,float c1,float c2){
return (e2-e1)/(c1+c2);
}
void makeTEqual(){
int itr;
//if ((time[0]==time[1]) && ( time[0]>time[2]))
{
if ((NoJ%2)==0)
//itr=
2006-12-01
05:47:39
·
2 answers
·
asked by
Anonymous
in
Computers & Internet
➔ Programming & Design