10 quarters and 3 dimes.
10 x $0.25 = $2.50
3 x $0.10 = $0.30
$2.50 + $0.30 = $2.80
2006-12-01 05:15:43
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answer #1
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answered by whawkeyes06 2
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If we let Q be the number of quarters and D be the number of dimes, we know that
D = Q - 7
And we know that
0.10 D + 0.25 Q = 2.80
So we substitute D with Q - 7
0.10 (Q - 7) + 0.25 Q = 2.80
0.10 Q - 0.7 + 0.25 Q = 2.80
0.35 Q - 0.7 = 2.80
0.35 Q = 3.50
Q = 3.50/0.35 = 10
Since Q = 10, D = Q - 7 = 10 - 7 = 3
So Bess has 10 quarters and 3 dimes. 10 quarters and 3 dimes adds up to $2.80, so we're in the clear.
2006-12-01 05:18:14
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answer #2
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answered by Puggy 7
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The mathematical way to do this one is:
.10*d+.25*q=2.80
q=d+7 (the number of dimes is 7 less than the number of quarters)
now plug in d+7 for q in the first equation:
.10*d+.25*(d+7)=2.80
Multiply by 100 to get a simpler to solve equation:
10d+25(d+7)=280
Simplify:
10d+25d+175=280
35d=105
d=3
because q=d+7
q=10
so 3 dimes and 10 quarters
(d=dime)
(q=quarter)
2006-12-01 05:21:14
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answer #3
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answered by D 3
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10 quarters 3 dimes
2006-12-01 05:12:25
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answer #4
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answered by MeanKitty 6
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Who needs all that difficult algebra? Here's the easy way :-
Take away the 7 extra quarters = $1.75.
That leaves $1.05, to be made up with the same number each of dimes and quarters.
One dime and one quarter = $0.35, so we need that three times over.
Three dimes, three quarters, and the seven quarters we accounted for at the beginning makes three dimes and ten quarters altogether.
2006-12-01 07:54:31
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answer #5
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answered by Anonymous
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First, set up an equation:
x = number of quarters
(x - 7) = number of dimes
Therefore,
0.25x + 0.10(x - 7) = 2.80 --- Multiply the 0.10 throughout the parentheses...
0.25x + 0.10x - 0.70 = 2.80 --- Combine like terms...
0.35x - 0.70 = 2.80 --- Add 0.70 to both sides...
0.35 = 3.50
x = 10
x - 7 = 10 - 7 = 3
ANSWER: There are 10 quarters and 3 dimes.
CHECK: 0.25(10) + 0.10(3) = 2.80
2.50 + 0.30 = 2.80
2.80 = 2.80 ---Answer checks out!
2006-12-01 05:19:44
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answer #6
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answered by Anonymous
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This is a simple lesson in simultaneous linear equations.
D = number of dimes
Q = number of quarters
25Q + 10D = 280
and
D = Q - 7
So, substitute either D or Q from the second equation into the first equation, and solve the first equation for Q or D, and then plug that number into the second equation for whichever you did not solve for in the first.
Clear?
2006-12-01 05:16:10
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answer #7
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answered by themountainviewguy 4
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10qs 3 ds
10*.25=2.50+30=2.80
10*7=3
2006-12-01 05:19:07
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answer #8
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answered by Lizard 2
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10 .25
3 .10
2006-12-01 05:12:07
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answer #9
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answered by USMCstingray 7
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