2006-12-01 02:55:58 · 12 answers · asked by yo yo ma 2 in Science & Mathematics ➔ Physics
It is a common assumption that heavier objects fall faster than lighter ones do. This is completely untrue. Every freely falling object, regardless of its mass, will accelerate at the same rate (9.8 meters per seconds squared near the surface of the Earth).
Try dropping your shoes from shoulder height when one is filled with something heavy and the other empty. If they both hit the floor at the same time, you have proved this point.
2006-12-01 03:27:19 · answer #1 · answered by Pey 7 · 0⤊ 0⤋
You state that the force 'on' a 2kg rock is twice as great as that 'on' a 1kg rock. The acceleration of these rocks is caused by the curvature of space-time around the mass of the planet earth (for example), so their acceleration would be the same as this force is not acting 'on' the rocks, it is the force 'from' the rocks. It would take more force to STOP the heavy rock falling. Whilst they would accelerate at the same speed, they wouldn't necessarily fall at the same speed in the atmosphere. The air provides a force on the rocks called air-resistance. This is dependant on the size and shape of the rocks. Curiously, it is a reactive force which means that the more force the rock applies to the air, the more resistance the air puts up! In other words, it is the size and shape of the rock that determines their speed in air.
No air? No difference in speed.
Got air but no difference in size and shape of rocks? No difference in speed.
NOTE: This relies on the linear relationship between applied force and resistive force. This relationship becomes non-linear when the forces grow too large. That shouldn't effect you until you reach degree-level physics though.
2006-12-01 03:35:20 · answer #2 · answered by Mawkish 4 · 0⤊ 0⤋
Yes, the force on a 2kg rock is twice as great as the other rock. But the larger force has an object 2X as massive to move.
F = W = (2*m)*g
But
a = F/m = (2*m)*g / (2*m) = g
2006-12-01 03:09:15 · answer #3 · answered by sojsail 7 · 0⤊ 0⤋
nicely shall we anticipate of of it from a distinct perspective. Gravity is a continuing acceleration. So once you've 2 gadgets placing out at relax a lengthy way above the floor and also you drop them, they are going to accelerate on the same fee. Acceleration is replace in speed divided with the aid of the replace in time. because the the acceleration is an similar and the time is an similar for both the replace in speed must be the same.Now shall we are saying you've a VW malicious program and a sidestep Ram, both at relax then accelerate at 5m/s/s. The rigidity on the sidestep is for sure higher because Fnet=ma. even if, after a given era of time they could have both received the same speed because the acceleration is an similar. 2as=v^2 - u^2. that is the equation for consistent acceleration, self sustaining of mass! the same is going for the different acceleration equations, s= a million/2at^2 + ut and a=delta v/ time. i wish this, quite lengthy, rationalization helped.
2016-11-28 03:44:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Because the 2kg rock has to overcome twice as much inertia to accelerate to the same speed.
2006-12-05 02:30:06 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Terminal velocity? LOL! It's Newton's law. You can drop a feather and a bowling ball in a vacuum and they will fall at the same speed. The force of gravity is constant on all objects regardless of weight. Terminal velocity is determined by wind resistance.
2006-12-01 03:09:46 · answer #6 · answered by Anonymous · 0⤊ 0⤋
The masses are different, but the only force acting on either is Gravity. Now if you APPLIED force and THREW one down, the forces would be different. But if you drop them, it's the same.
There is a different force required to HOLD them in the air. The 2kg rock is indeed heavier to HOLD. But you're talking about dropping them.
2006-12-01 03:04:19 · answer #7 · answered by Michael 2 · 0⤊ 1⤋
Back to your books!
The Force applied depends on the mass: f = m.a. In a free fall object, f = m.g (gravity, 9.81 ms-2).
So, ok, the FORCE depends on the mass.
But the velocity?
The velocity does NOT depend on the mass:
v = a . t (acceleration x time).
So, the speed of falling objects does NOT depend on the gravitational force applied on them...
2006-12-01 03:50:10 · answer #8 · answered by just "JR" 7 · 0⤊ 0⤋
Because the inertia of the 2 Kg. rock is exactly twice the inertia of a 1 Kg. rock.
2006-12-01 03:04:08 · answer #9 · answered by Joe 5 · 0⤊ 1⤋
mass of a body has no link with its velocity when it is droped downward.it is entirely due to gravity that the two stones fall together.
2006-12-01 04:38:07 · answer #10 · answered by Harry Potter 2 · 0⤊ 0⤋