For extremely small values of x, cosx=x
2006-12-01 01:50:58
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answer #1
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answered by ganesh 1
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Substitute the value if you can: sin 0 = 0 and cos 0 =1 sinx and cosx do not have a limit as x -> inf, so those limits DNE
2016-05-23 07:36:28
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answer #2
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answered by Anonymous
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only one solution draw the graphs of y = cosx and y = x to prove that
2006-12-01 02:40:00
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answer #3
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answered by James Chan 4
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Only one solution.You need to draw graphs of both y=cosx and y=x . The point of intersection of both these graphs will give the solution.
2006-12-02 00:48:27
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answer #4
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answered by ~champagneonice~ 2
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Draw the graphs of functions
y=cos (x), y=x on the same plane
Number of points of intersection=Number of solutions
=>Only one solution
Solving analytically will take ages!
2006-12-03 18:40:56
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answer #5
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answered by Anonymous
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There is only one exact solution to cos x = x. That is when x = 42.3464591 degrees (to nine significant figures). This only works if you work in radians, where this angle x = 0.73908513784. In this situation:
0.73908513784 = cos(0.73908513784)
2006-12-01 03:03:31
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answer #6
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answered by Mawkish 4
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Only 1 solution.
.73908 (in radians)
which is the same as
.99985 (in degrees)
2006-12-01 01:51:12
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answer #7
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answered by ninja boy 2
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there is no as such way to do that
the only way is that
firstly x lies in(-1,1)
draw y=x (note ; draw on agraph paper)
y=cos x
clearly they have only solution in(-1,1)
now this value is a real value which is non repeatable
& non terminating but close to 0.99
(u can check out from calculator)
thanks & good luck & good question
2006-12-01 01:56:59
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answer #8
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answered by sidharth 2
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only one solution
2006-12-01 17:03:12
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answer #9
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answered by arpita 5
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only one solutions i.e.X=
0.9998477415310881129598107686798(degrees) or
0.73908513321516064165531208767387(radians) or
0.99987666291073963586174574244615(grads)
2006-12-01 01:56:18
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answer #10
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answered by Anonymous
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