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Military specs oftan call for electronic devices to be able to withstand accelerations of 10 g. To make sure that they do, manufacturers test them using a shaking table that can vibrate a device at various specified frequencies & amplitudes. If a device is given a vibration of amplitude 9.7 cm, what should its frequency be in order to test for compliance with the 10 g requirement (ans in Hz)?

d = v*t + 0.5*a*t^2 = 9.7sin(x*t)
take the derivative
v + a*t = 9.7x*cos(x*t)
take the derivative
a = 9.7*x^2*-sin(x*t)

so:
10g = 9.7*x^2
x^2 = 10*9.8/9.7
x = 10.1

2pi = 10.1*T
T = 0.62 sec

freq = 1/T
freq = 1/0.62
freq = 1.61 Hz

2006-12-01 00:55:37 · 2 answers · asked by Mariska 2 in Science & Mathematics Physics

2 answers

Since it is the case of simple harmonic motion, the equations of motion will not hold good here.
The maximum acceleration in this case is given by
a = r ω^2 ; r = amplitude(0.097m) ,
ω = angular frequency , a = 10 g
=> a = 4π r f^2 ; f = frequency
=> f = sqr root ( 10 g / 4πr)
use this formula. use only S.I. units and you will definitely get the answer

2006-12-01 02:39:02 · answer #1 · answered by Anonymous · 0 0

I think you are mixing units.
9.7 cm/sec vs. 9.8 meters/sec.
Change centimeters into meters, and I'll bet it will be OK.

2006-12-01 08:59:11 · answer #2 · answered by firefly 6 · 1 0

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