please answer and please show the solution
how to eliminate the arbitrary constant>> xy^2-1=cy
2006-11-30 17:28:09 · 6 answers · asked by sheryl 1 in Science & Mathematics ➔ Engineering
xy^2-1/cy=0
ie; xy^2/cy - cy =0.
ie; xy^2=c^2y^2
ie; c=squre root of x
substitute in original equation and c is eliminated.
Ans;xy^2-1=squ.root.x.y
2006-12-02 05:29:09 · answer #1 · answered by Mathew C 5 · 0⤊ 0⤋
u can convert the equation to a differential equation
u need to differentiate the expression one time to eliminate the constant 'c'.
xy^2-1/y=c
differentiate both sides 'c' becomes 0.
2006-12-01 02:12:29 · answer #2 · answered by devil_b 2 · 0⤊ 0⤋
c = x( y - 1/y)
2006-12-01 02:11:24 · answer #3 · answered by Siva 2 · 0⤊ 0⤋
by differentiating the function as many times as the no of arb consts.
2006-12-01 01:50:49 · answer #4 · answered by rajesh 1 · 0⤊ 0⤋
Do they give more info than just that?
2006-12-01 01:30:11 · answer #5 · answered by Julio Cesar C 2 · 1⤊ 0⤋
c=[x*y-1/y]
differentiating with respect to "x"
0=[y+xdy/dx-1/y*y]
x*dy/dx=[(1/y*y )-y]
dy/dx=[1-(y*y*y)]/(x*y*y)
2006-12-02 06:21:14 · answer #6 · answered by avinash8891 1 · 0⤊ 0⤋