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I know that on ECG, with unstable angina you get ST depression and with M.I. you get ST elevation. But how come two similar conditions produce completely opposite actions on ECG? I've read up on it and I can't find a simple answer. Can anyone explain to me simply why this happens?

2006-11-30 08:56:53 · 3 answers · asked by Xenophonix 3 in Science & Mathematics Medicine

3 answers

In an MI there is dead tissue, so the electrical current is completely different to angina when the tissue is still alive but ischaemic. Not a full explanation but goes some way to explain it?

2006-11-30 09:01:24 · answer #1 · answered by teary chocolate 3 · 0 0

ST depression occurs with angina-this is just an indication that the heart is stressed but has not sustained a cardiac event. ST elevation occurs after a person has actually had a heart attack-it is an indication that heart has been damaged. This ST elevation will always be apparent on an ECG after a person has had an MI

2006-12-02 14:23:53 · answer #2 · answered by Anonymous · 0 0

The ECG result is part dependant on the state of the patients mind at the time of the test, that's why it may be taken several times to get a true reading.

2006-11-30 08:59:34 · answer #3 · answered by tucksie 6 · 0 2

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